One bullet is fired horizontally and simultaneously a second bullet is dropped from the same height. Neglecting air resistance and assuming the ground is level, which bullet hits the ground first?
Content Times:
0:15 Reading the problem
0:53 Lis...ting the known variables
1:59 Determining the answer
2:37 Demonstrating the answer
3:00 Isn’t one moving faster?
3:52 The Review. Total time: (04:13)[more]

My strategy for solving any projectile motion problem. You need to split the variables in to the x and y directions and solve for time. Sounds simple and it really is, usually.
Content Times:
0:11 Review of Linear Motion Examples
0:57 Introduci...ng Projectile Motion!
1:48 Basic strategy for solving any projectile motion problem
2:06 The y-direction (UAM)
3:22 The x-direction (constant velocity)
4:36 How many knowns do you need in each direction?
5:41 What do we usually solve for?
6:12 The Review Total time: (06:57)[more]

This time in our projectile motion problem, we know the displacement in the y-direciton and we are solving for the displacement in the x-direciton. We could you use the quadratic formula and I even show you how, however, I also show you the way I re...commend doing it which avoids the quadratic formula.
Content Times:
0:14 Reading the problem
0:55 Comparing the previous projectile motion problem to the current one
1:16 Breaking the initial velocity in to its components
1:44 Listing the givens
2:27 Beginning to solve the problem in the y-direction
3:08 The Quadratic Formula!
5:49 How to solve it without using the quadratic formula. Solve for Velocity Final in the y-direction first
6:59 And then solve for the change in time
8:12 Solving for the displacement in the x-direction
9:01 Showing that it works
9:43 The Review. Total time: (10:30)[more]

Now that we have dropped the ball into the bucket, we can determine the final velocity of the ball right before it strikes the bucket. Don’t forget that velocity is a vector and has both magnitude and direction. Yep, component vector review!
Cont...ent Times:
0:34 Finding the final velocity in the y direction.
1:52 We need to find the hypotenuse!
2:28 Finding the final velocity in the x direction.
2:57 Finding the magnitude of the final velocity.
4:06 Finding the direction of the final velocity.
5:08 The number answer.
5:52 Visualizing the answer.
6:28 Why is the ball always right below mr.p's hand?
7:07 Doesn’t the ball travel farther than mr.p’s hand?
7:33 The Review. Total time: (07:57)[more]

Projectile motion is composed of a horizontal and a vertical component. This video shows that via a side-by-side video demonstration and also builds the velocity and acceleration vector diagram.
Content Times:
0:14 Reviewing Projectile Motion
1:...00 Introducing each of the video components
1:40 Building the x-direction velocity vectors
2:15 Building the y-direction velocity vectors
3:12 Combing velocity vectors to get resultant velocity vectors
3:41 Showing how we created the resultant velocity vectors
4:47 Adding acceleration vectors in the y-direction
5:28 Adding acceleration vectors in the x-direction
5:45 Completing the Velocity and Acceleration diagram
5:58 The diagram floating over clouds, i mean, why not, eh?
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Multilingual? Please help translate Flipping Physics videos!
Next Video: Skateboarding Frame of Reference Demonstration
Previous Video:The Classic Bullet Projectile Motion Experiment
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Learn how to derive the Range of Projectile. The Horizontal Range of a Projectile is defined as the horizontal displacement of a projectile when the displacement of the projectile in the y-direction is zero.
Content Times:
0:12 Defining Range
0:...32 Resolving the initial velocity in to it’s components
1:49 Listing our known values
2:49 Solving for range in terms of change in time
3:30 Solving for the change in time in the y-direciton
5:18 Combining two equations
6:03 The Sine Double Angle Formula
6:53 The Review
Want Lecture Notes?
Next Video: A Range Equation Problem with Two Parts
Previous Video: Understanding the Range Equation of Projectile Motion
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Mr.p throws a ball toward a bucket that is 581 cm away from him horizontally. He throws the ball at an initial angle of 55° above the horizontal and the ball is 34 cm short of the bucket. If mr.p throws the ball with the same initial speed and the ...ball is always released at the same height as the top of the bucket, at what angle does he need to throw the ball so it will land in the bucket?
Content Times:
0:14 Reading the problem
1:01 Why we can use the Range Equation
2:15 Listing what we know for the first attempt
3:06 Solving for the initial speed
4:26 Solving for the initial angle
5:45 Putting the ball in the bucket
6:15 There are actually two correct answers
6:44 It took quite a few attempts
Want Lecture Notes?
Next Video: The Classic Bullet Projectile Motion Experiment
Previous Video: Deriving the Range Equation of Projectile Motion
"Walk Away" by Bella Canzano from her EP "A Secret That You Know"
Music used by permission of the artist.
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Can you drop a ball from a moving vehicle and get it to land in a bucket? You can using Physics! In this video we solve an introductory projectile motion problem involving an initial horizontal velocity and predict how far in front of the bucket to ...drop the ball.
Content Times:
0:17 Reading the problem.
0:41 Visualizing the problem.
1:18 Translating the problem.
2:31 Converting from miles per hour to meters per second.
3:10 Two common mistakes about projectile motion givens.
4:29 Beginning to solve the problem.
5:13 Solving for the change in time in the y-direction.
6:22 Solving for the displacement in the x-direction.
7:29 Video proof that it works.8:14 Air resistance. Total Time: (09:41)[more]

The Horizontal Range of a Projectile is defined as the horizontal displacement of a projectile when the displacement of the projectile in the y-direction is zero. This video explains how to use the equation, why a launch angle of 45° gives the maxim...um range and why complimentary angles give the same range.
Content Times:
0:16 Defining Range
0:50 How can the displacement in the y-direction be zero?
1:21 The variables in the equation
2:09 g is Positive!
3:05 How to get the maximum range
4:17 What dimensions to use in the equation
5:19 The shape of the sin(θ) graph
6:17 sin(2·30°) = sin(2·60°)
7:35 A graph of the Range of various Launch Angles
8:18 The Review Total Time: (08:52)[more]

An introductory projectile motion problem where you have to break the initial velocity vector in to its components before you can work with it. The Nerd-A-Pult is the perfect tool for showing projectile motion.
Content Times:
0:02 Introducing the... Nerd-A-Pult
0:43 Demonstrating the marshmallow capabilities of the Nerd-A-Pult
1:18 Reading the problem
2:26 Starting to solve the problem
3:03 What do we do with the initial velocity?
3:45 Solving for the initial velocity in the y-direction
4:27 Solving for the initial velocity in the x-direction
5:13 Deciding which direction to start working with
5:38 Solving for the change in time in the x-direction
6:34 Solving for the displacement in the y-direction
7:54 Proving that our answer is correct
8:58 The Review
Want Lecture Notes?
Next Problem: Nerd-A-Pult - Measuring Initial Velocity
Nerd-A-Pult #2 – Another Projectile Motion Problem
Previous Problem: An Introductory Projectile Motion Problem with an Initial Horizontal Velocity
Want a Nerd-A-Pult? You can purchase one at marshmallowcatapults.com
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